What is the difference between Go's type inference and explicit typing in Go?

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Jayant Kumar · Accepted Answer

Go is a statically-typed language, which means that all variables and expressions have a type that is determined at compile-time. Go provides two ways to specify the types of variables and expressions: explicit typing and type inference.
Explicit typing involves explicitly declaring the type of a variable or expression using a type declaration. 
For example, to create an integer variable in Go using explicit typing, you would use the following syntax:
var i int = 10

Type inference, on the other hand, allows the Go compiler to automatically determine the type of a variable or expression based on its context. This is done using the **:=** syntax, which declares and initializes a variable in one step. 
For example, to create an integer variable using type inference, you would use the following syntax:
i := 10

In this case, the type of the **i** variable is inferred by the Go compiler to be **int** based on the value assigned to it.
The main difference between explicit typing and type inference is that with explicit typing, the programmer must explicitly declare the type of the variable or expression, while with type inference, the Go compiler automatically determines the type based on the context. This can make code shorter and more concise, but may also make it less clear to read and understand. Explicit typing can also help catch type errors at compile-time, while type inference may lead to more subtle errors that are not caught until runtime.

What is the difference between Go's type inference and explicit typing in Go?

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What is the difference between Go's type inference and explicit typing in Go?

Jayant Kumar @jayantkumar314

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